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15/06/2024

Solution to the Simultaneous equation posted earlier
Using Elimination method

To solve this system of linear equations simultaneously, we can use the method of substitution or elimination. Here, we'll use the elimination method.

First, let's rewrite the equations:

Equation 1: 2x + 3y - 5z = 8
Equation 2: 3x - 2y - 3z = -3
Equation 3: 2x + 5y + 8z = 27

Our goal is to eliminate one variable at a time. Let's start by eliminating x.

Multiply Equation 1 by 3 and Equation 2 by 2 to make the coefficients of x equal:

Equation 1': 6x + 9y - 15z = 24 (multiplied by 3)
Equation 2': 6x - 4y - 6z = -6 (multiplied by 2)

Now, subtract Equation 2' from Equation 1' to eliminate x:

(6x + 9y - 15z) - (6x - 4y - 6z) = 24 - (-6)

This simplifies to:

13y - 9z = 30 ... (Equation 4)

Now, let's eliminate x from Equation 3 by subtracting Equation 1 from Equation 3:

Equation 3' = Equation 3 - Equation 1
2x + 5y + 8z = 27
- (2x + 3y - 5z = 8)

This simplifies to:

2y + 13z = 19 ... (Equation 5)

Now we have two equations with two variables:

Equation 4: 13y - 9z = 30
Equation 5: 2y + 13z = 19

Multiply Equation 4 by 2 and Equation 5 by 13 to make the coefficients of y equal:

Equation 4': 26y - 18z = 60 (multiplied by 2)
Equation 5': 26y + 169z = 247 (multiplied by 13)

Now, subtract Equation 4' from Equation 5' to eliminate y:

(26y + 169z) - (26y - 18z) = 247 - 60

This simplifies to:

187z = 187

Divide by 187:

z = 1

Now that we have the value of z, substitute it into one of the equations with two variables (y and z) to find the value of y. We'll use Equation 4:

13y - 9z = 30
13y - 9(1) = 30
13y - 9 = 30
13y = 39
y = 3

Finally, substitute the values of y and z into one of the original equations to find the value of x. We'll use Equation 1:

2x + 3y - 5z = 8
2x + 3(3) - 5(1) = 8
2x + 9 - 5 = 8
2x+4=8
2x=8-4
2x = 4
x = 2
Hance :
x = 2
y = 3
z = 1

I hope u understand 🤗🤗

15/06/2024

Nice solution from one of our top fans Kent Darunday

2x+3y-5z=8 eq1.
3x-2y-3z=-3 eq2.
2x+5y+8z=27 eq3.

Minus eq1 to eq3.
(2x+3y-5z=8)-(2x+5y+8z=27)
Result: 2y+13z=19 or 2y=19-13z or y=(19-13z)/2 this is eq4.

Substitute 2y from eq4 to eq2.
3x-2y-3z=-3
3x-(19-13z)-3z=-3
3x+10z=16 this is eq5.

Add eq1 and eq2 then the answer is add to eq3.
(2x+3y-5z=8)+(3x-2y-3z=-3)
5x+y-8z=5
(5x+y-8z=5)+(2x+5y+8z=27)
Result is 7x+6y=32 or x=(32-6y)/7 this is eq6.

Substitute eq6 to eq5.
3x+10z=16
x=(32-6y)/7
3 ((32-6y)/7) +10z=16
96/7 - 18/7 + 10z=16
(96/7 - 18/7 y + 10z=16) (1/2)
48/7 -9/7 y +5z=8
-9/7 y +5z = 8/7 this is eq7

Substitute eq4 to eq7 to get z.
-9/7 ((19-13z)/2) +5z = 8/7
-171/14 + 117/14 z + 5z =8/7
187/14 z = 187/14
z=1

Substitute z to eq4 to get y.
y=(19-13z)/2
z=1
y=(19-13(1))/2
y=(19-13)/2
y= 6/2
y=3

Substitute y to eq6.
x=(32-6y)/7
y=3
x=(32-6(3))/7
x=(32-18)/7
x=14/7
x=2

14/06/2024

Solve Simultaneously
2x+3y-5z=8
3x-2y-3z=-3
2x+5y+8z=27

13/06/2024

Solution to the Question Posted earlier 🤗🤗

12/06/2024

Prepared this for one of our top fans Dennis Kinyua
U will be the next
Topic: Matrices
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11/06/2024

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11/06/2024

A + B = 60
A - B = 40
2A - 9B = ?

11/06/2024

Try this
I will post solution later 🤗
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10/06/2024

Thanks for being a top engager and making it on to my weekly engagement list! Timothée Tesla, Dennis Kinyua

10/06/2024

What fraction must be subtracted from the sum of 2⅙ and 2 ⁷/12 to give 3¼ ?

08/06/2024

Welcoming remark for our top fans.
Suggest a topic and we will make a lesson plans for you

22/05/2024

Shout out to my newest followers! Excited to have you onboard! Patrick Antwi, Cyrus Damoi Cammue, David Anyisisye, Nasrullah Mardanzai, E Sowani E Sowani, Wongani Wongie Kamanga, Fabiema T. Sammy, Naasir Abiib, Qazi Muhammad Arsal Haider, Salemah Bt Ahamad, Malick Mbaye, Ayoade Samson Alagbe, Judith Mzuba, Alexy Smart, Azeem Khan, သဲဦးသီရိ မေ, Etz Emmanuella Ricardo, Yamkelani Mntuyedwa, Mehran Ali Ansari Mehran, Jeff Bowy, Amos F. Bowah, Mustafa Mulakha, Àyàm Dç Bàrôñ, Ethel Kanyumbu, Muhammadu Usman Mamu, Muazu Muhammad, Walbe Beji, Oluwa Tunmise Oluwa Pelumi, Nazish Nazish, Aleu Bak Bak, Jahid Hossain, Sieh Walloh, ហ៊ុំ រតនា, Charity Loveth, Emmanuel K. W. Pawoo, Eric Tetteh, Solomon Achiisa, Fanele Cele, Zakari Khadija Dahiru, Cathrina Persaud, Ebri Iwara, Adah Joseph, Arjun Chouhan

21/05/2024

Thanks for being a top engager and making it on to my weekly engagement list! Sanath Jayatissa, Silence Billonaire

17/05/2024

Solve using Elimination method
6/x - 4/y =1;
9/x - 8/y = 1

15/05/2024

Shout out to my newest followers! Excited to have you onboard! Chung A Lee, Mac Gregor, Salvation Jerry Testimony, Isa Yahaya, Vandrangi Lakshmana Das Patnaik, Philip Gwom, Sanath Jayatissa, Krishan Saikia, Muhammad Ahmad, ومجيحكسعتح ثسةسهح, Rasak Oluwanisola, Oscar Bagtasos, سيف صالح خضير, Aly El Salamounii, Muhammad Irfan Ullah Khan, Luckson Chisala, Naomi Njoroge, ዝምታ ነዉ መልሴ, Kamala Dalai, Øluwakunbi Dåmhîlølã, Kundan Sharma, Tesfamichael Bereket, Aaroshi Ârshi Aarosh, Onefeli Mercy, Emmanuel Abraham, AB Malik Sadiq, Prince Tano, Lawrence Rita, Alphanso Leo Gontee, Prëshy Jãy, Molla Getachew, Ama Bebe Jacobs, Ami New, Jôhñ Ñéll Best Kepa, Praise Anietie, Rhine Rhodes, David Aj, Jacty Ndash, Dahur July J, Ial Shahajn

11/05/2024

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10/05/2024

Is it possible to find a Quadratic equation which has Zero(0) to be one of it roots
e.g if the roots are
X=0 and X=-3

04/05/2024

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03/05/2024

Like and Shate

03/05/2024

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27/02/2024

Shout out to my newest followers! Excited to have you onboard! Emadh M. A Hasoun, Dennis Kinyua, Gabriel Finali

18/02/2024

NICE MATH CHALLENGE
x+y+z=100
√z+y=55
(√x)^6=?
y÷(z)²=?

17/02/2024

SOLVE for "n"
nⁿ=2²ⁿ
Very Simple but Tricky 💯
Give a try

16/02/2024

One of my followers asks me to prepare a note on the AP, and GP Series.
Please share with others Students across, and don't forget to Follow my page for more math lessons 👍🏼👍🏼

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